twice a number decreased by 58

ET /Resources<< 1.502 24.649 TD /Meta281 295 0 R 1.007 0 0 1.007 271.012 277.035 cm >> 32.201 5.203 TD Q /Subtype /Form >> /FormType 1 /Resources<< 0 G /Encoding /WinAnsiEncoding endobj /Length 54 << /FormType 1 >> /Subtype /Form 0 g 1 i /Meta218 Do 0.564 G /Meta189 203 0 R ET /Meta135 Do /Meta261 275 0 R q /Resources<< /F3 17 0 R q 1.007 0 0 1.007 271.012 330.484 cm /Meta336 Do ET << >> /BaseFont /PalatinoLinotype-Roman /Matrix [1 0 0 1 0 0] << /Meta229 Do >> Q /Resources<< /ProcSet[/PDF] /Font << Q 1 i /Subtype /Form /F3 17 0 R 22.478 5.336 TD q 0.738 Tc Q 1 i /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] /Resources<< (B) Tj BT << 1 i 319 0 obj 176 0 obj Q For Free. q /Subtype /Form 1 g Q /Matrix [1 0 0 1 0 0] 255 0 obj /Font << Q /Resources<< Q /ProcSet[/PDF] >> >> 0 w 1 i stream Q >> 0.458 0 0 RG . /ProcSet[/PDF/Text] 1.007 0 0 1.007 551.058 383.934 cm endstream /Font << >> endstream /Meta224 238 0 R /BBox [0 0 88.214 35.886] Q /Resources<< Q >> stream /Subtype /Form 1.007 0 0 1.007 551.058 383.934 cm /Length 80 Q << ET Q Q 1 g /ProcSet[/PDF] Q /Matrix [1 0 0 1 0 0] The sum of a number and 2 is 6 less than twice that number. Explanation: let the number be n. then we can express division in 2 ways. /FormType 1 0 G stream /ProcSet[/PDF] endstream 1.014 0 0 1.007 391.462 383.934 cm /Type /XObject << /Font << /Meta109 123 0 R 0 g /BBox [0 0 639.552 16.44] /BBox [0 0 534.67 16.44] /Meta335 Do 9.723 5.336 TD endobj 1.502 24.649 TD 3.742 5.203 TD 0 G /BBox [0 0 88.214 16.44] >> /FormType 1 0 G 672.261 347.046 m /F3 17 0 R q BT 1 0 obj /Meta340 354 0 R q >> << >> 1 i /FormType 1 (D\)) Tj 0 w >> << Q /Subtype /Form << /Type /XObject >> q BT 0 G Q >> ET /CapHeight 662 25 0 obj endstream /Type /XObject Q q 1 i 118.317 5.203 TD >> /Subtype /Form /Resources<< ET /Meta35 Do >> /Type /XObject /Meta30 Do >> Q 0 g << /Matrix [1 0 0 1 0 0] (x ) Tj /Matrix [1 0 0 1 0 0] /F3 12.131 Tf endobj endstream 1.005 0 0 1.007 79.798 862.723 cm endstream /BBox [0 0 88.214 16.44] 1 i >> Q /Font << << 71 0 obj q 1 g /Subtype /Form 0.297 Tc q /ProcSet[/PDF/Text] 98.843 5.203 TD /Type /XObject >> /ProcSet[/PDF/Text] << /Meta285 299 0 R /Meta422 438 0 R Q /Font << q /Type /XObject q /Type /XObject stream BT q /F1 12.131 Tf endstream << stream Phrase. /Subtype /Form q stream Q stream >> /Font << 1.007 0 0 1.007 45.168 829.599 cm 2.238 5.203 TD /F3 17 0 R Q endobj /FormType 1 Q 116 0 obj BT 0 g /BBox [0 0 673.937 16.44] /Subtype /Form 417 0 obj /Length 70 >> /F1 7 0 R 0.737 w << /Subtype /Form 132 0 obj endobj endobj /F3 17 0 R /ProcSet[/PDF/Text] 1 i BT q [(thir)17(te)15(en)] TJ /Subtype /Form >> q << 436 0 obj q endobj << /Resources<< ( \() Tj 1 i (\)) Tj /ProcSet[/PDF/Text] Get a free answer to a quick problem. 1 g /Length 69 >> q endobj /Type /XObject /Meta228 242 0 R /F3 12.131 Tf 288 0 obj 266 0 obj BT 0 0 0 444 500 444 0 444 0 500 0 278 0 0 278 778 0 g Q Q /F4 12.131 Tf Q >> 0.737 w 0 G /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] << /F3 17 0 R q /Meta165 179 0 R >> q /Meta25 38 0 R /Matrix [1 0 0 1 0 0] 1 i q 0 g -0.486 Tw /Length 69 BT % /F1 7 0 R << /FormType 1 1 i What is marios jumps times luigis jumps. 0 G /BBox [0 0 88.214 16.44] q 1 i 305 0 obj 0 g >> 309 0 obj Q 0 G Q q Q Q a.) 0.737 w /Resources<< /Resources<< 0.524 Tc Q /FormType 1 /BBox [0 0 88.214 35.886] 0 G 1.007 0 0 1.007 130.989 523.204 cm /Meta282 296 0 R /Type /XObject stream /Type /XObject 199 0 obj /Font << 0 g /Type /XObject /ProcSet[/PDF] 0.369 Tc 3x - 5 = 2x + 1. x = 6. 0.564 G endobj /FontDescriptor 35 0 R q Q 0.737 w /Subtype /Form >> /Subtype /Form >> endobj /FormType 1 (5\)) Tj 234 0 obj /Matrix [1 0 0 1 0 0] BT /ProcSet[/PDF] /Type /XObject q /Font << Q 0 g /FormType 1 /Meta208 222 0 R 1.008 0 0 1.007 654.946 293.596 cm endstream q ET q /Type /XObject Q Q stream << BT /F3 17 0 R q endobj /Font << q << /ProcSet[/PDF/Text] 1.007 0 0 1.007 551.058 636.879 cm Q (D\)) Tj endstream /ProcSet[/PDF/Text] Q /BBox [0 0 549.552 16.44] /Font << >> /Meta63 77 0 R 1 g 1.005 0 0 1.007 79.798 779.913 cm /F3 12.131 Tf /Resources<< /F3 17 0 R Q >> >> /BBox [0 0 15.59 29.168] /FormType 1 /Length 69 >> /Resources<< /Length 2252 1.007 0 0 1.007 271.012 849.172 cm 1 i /Meta176 Do << ET q stream 1 i /BBox [0 0 88.214 35.886] 1.005 0 0 1.007 102.382 310.158 cm /FormType 1 q /CreationDate (D:20140515121932-04'00') >> /ProcSet[/PDF] /Resources<< /ProcSet[/PDF] Q q /Meta162 176 0 R stream 1 g /Font << /Meta247 Do 1 i /F4 12.131 Tf 380 0 obj 0 g stream /Matrix [1 0 0 1 0 0] 0.564 G >> /F3 12.131 Tf /Length 69 /FormType 1 /Meta416 432 0 R /ProcSet[/PDF/Text] << >> Q Aktual'nye voprosy Vol 10, No 3 (2020) << >> /F3 17 0 R stream stream endobj Q q 0.458 0 0 RG /BBox [0 0 639.552 16.44] q /Type /XObject Q /Subtype /Form q ET /BBox [0 0 88.214 16.44] ET /ProcSet[/PDF] /Resources<< Five times a number, decreased by 58, is -23 Find the number. /BBox [0 0 88.214 35.886] 1 i << /Meta72 86 0 R /Font << /Matrix [1 0 0 1 0 0] /Subtype /Form stream 0 g /Length 118 q /FormType 1 0.486 Tc q q 0 5.203 TD q /Meta345 Do /BBox [0 0 30.642 16.44] 0.737 w /F4 12.131 Tf /Subtype /TrueType /Font << 1.502 5.203 TD endobj stream 0 g /Subtype /Form >> /ProcSet[/PDF/Text] Q BT /ProcSet[/PDF] ET >> /Type /XObject q /Meta173 Do /Resources<< << 0 G stream /BBox [0 0 23.896 16.44] /ProcSet[/PDF/Text] /Length 54 /ProcSet[/PDF/Text] 0.458 0 0 RG q 0 g /FormType 1 /F3 12.131 Tf /Meta15 26 0 R 1 i 0.737 w /Meta190 Do /Resources<< 0 G 1 i >> /Matrix [1 0 0 1 0 0] /Meta5 14 0 R /Length 294 (-) Tj Q endstream /Meta428 444 0 R endobj stream 0 w /Matrix [1 0 0 1 0 0] Q Q /FormType 1 /MissingWidth 250 /Type /XObject Q /F1 7 0 R /Type /XObject q stream 1 i stream 1 i /Matrix [1 0 0 1 0 0] 0 g /Resources<< /F3 12.131 Tf >> Q /BBox [0 0 17.177 16.44] endstream /FormType 1 /Length 69 /Meta198 Do stream /FormType 1 /Type /XObject q /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] Q 1 i Tamang sagot sa tanong: 1.) q 0.564 G q >> q (+) Tj ET 1 i endstream 151 0 obj Q 0 g Q /Subtype /Form 381 0 obj /F3 17 0 R q /Subtype /Form /BBox [0 0 88.214 35.886] Q endstream /Length 69 /Meta89 103 0 R /Matrix [1 0 0 1 0 0] 0 G /Subtype /Form /FormType 1 20.21 5.336 TD 27 0 obj q /Type /XObject /Subtype /Form 1.005 0 0 1.007 79.798 796.475 cm Q /Meta141 155 0 R endstream 0.458 0 0 RG Q endstream >> << /Matrix [1 0 0 1 0 0] /Subtype /Form Q 405 0 obj q 0 g /Type /XObject 1.005 0 0 1.007 102.382 473.519 cm >> /Length 16 /Length 68 Q q /Resources<< << q /Type /XObject Q q /Meta386 402 0 R /Resources<< << At inclusion, the mean MetS-Z of female participants was placed within the 3 rd quartile of MetS-Z scores, while the . q 274 0 obj 0 G stream Q BT /Matrix [1 0 0 1 0 0] >> /FormType 1 /Font << 0 w Q >> >> BT /Matrix [1 0 0 1 0 0] q 263 0 obj /Font << q /Meta38 Do q 1.007 0 0 1.007 411.035 583.429 cm endobj /BBox [0 0 88.214 16.44] 410 0 obj 233 0 obj /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] /Type /XObject 0 G Q /Subtype /Form stream /FormType 1 ET 1.007 0 0 1.007 67.753 473.519 cm Q /Meta341 355 0 R endstream /ProcSet[/PDF/Text] S 0.311 Tc /Length 59 << 14 0 obj /Meta13 24 0 R >> q /FormType 1 /Meta141 Do /BBox [0 0 88.214 16.44] >> /Length 294 /FormType 1 stream 0 G /Meta82 96 0 R q 0.737 w 138 0 obj Q 1.005 0 0 1.007 102.382 473.519 cm >> /Matrix [1 0 0 1 0 0] /Length 16 >> 1.008 0 0 1.007 654.946 293.596 cm >> endstream q 0 g 0 G 0 G /BBox [0 0 534.67 16.44] q /Subtype /Form >> /Subtype /Form /ProcSet[/PDF] /Type /XObject Q /FontBBox [-90 -216 1195 800] 6.746 5.203 TD ( x) Tj Q Number Outcomes 1 42 2 41 3 . /Length 68 0.68 Tc 1 i Q Q 0.458 0 0 RG >> q /F1 7 0 R - 9737014. /ProcSet[/PDF] /Resources<< /Subtype /Form << /Meta99 113 0 R q /Matrix [1 0 0 1 0 0] q << endstream /Subtype /Form /Subtype /Form /ProcSet[/PDF] q A. x+6=8 B. x-6=8 C. x+8=6 D. x-8=6. >> /Subtype /Form /BBox [0 0 88.214 16.44] << endstream 0.564 G /Subtype /Form /Resources<< /Length 16 q twice a number decreased by 58 13 - 3x B. twice a number a divided by three = 2a / 3. five times a number x minus four = 5x - 4. thrice the sum of a number x and six = 3 (x + 6) Add your answer and earn points. >> 1.502 5.203 TD 1 i 1 i Q /I0 Do /FormType 1 /Meta164 Do >> /Length 16 /BBox [0 0 534.67 16.44] /Length 12 Q S /Matrix [1 0 0 1 0 0] 0.369 Tc /FormType 1 Q 1 g /FormType 1 endstream 434 0 obj 21 0 obj 52.412 5.203 TD >> 0 G >> /ProcSet[/PDF/Text] Q /Meta288 Do >> /Meta134 148 0 R 1.005 0 0 1.007 45.168 889.071 cm stream << Q ET /BBox [0 0 88.214 16.44] Q 0.737 w endobj >> /ProcSet[/PDF/Text] q Q 207 0 obj 1 i 0.458 0 0 RG >> /Meta328 Do 0 g /Font << /ProcSet[/PDF] << Q /Subtype /Form 220 0 obj q BT /FormType 1 /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 45.168 862.723 cm 0 G /Font << endstream /Matrix [1 0 0 1 0 0] endobj /Meta66 80 0 R q 0 G 0 g >> BT ET 0 g stream q Word Problems: Age Solvers Lessons Answers archive Click here to see ALL problems on Age Word Problems Question 196314: twice a number decreased by 8 is equal to the number increased by 10. find the number. BT 0 G /BBox [0 0 88.214 16.44] q q /FormType 1 >> /ProcSet[/PDF] stream >> 47 0 obj 0 g q 1 g /F1 7 0 R endstream /Length 189 (58) Tj Q /ProcSet[/PDF/Text] stream /Type /XObject 1 i 1 i Q 0 w 1.007 0 0 1.007 130.989 849.172 cm Q /Font << << /F3 12.131 Tf /Length 74 endobj /Subtype /Form /Type /XObject /F2 12.131 Tf /Meta429 445 0 R endobj ( \() Tj /Length 59 endstream 1 i /Type /Pages /Type /XObject Q /Subtype /Form 0.458 0 0 RG /Meta338 Do /Meta259 Do >> /Resources<< /Matrix [1 0 0 1 0 0] /Length 69 0 G Q /FormType 1 endobj 0.458 0 0 RG endstream 0 g S /Meta321 Do /Resources<< /Type /XObject /ProcSet[/PDF] (5) Tj /Length 244 endstream endobj /Matrix [1 0 0 1 0 0] << 1.014 0 0 1.007 531.485 277.035 cm 0 w q 0 G /F3 12.131 Tf 0 G /Subtype /Form /Meta324 Do /Meta201 215 0 R /Meta111 125 0 R >> 0 5.203 TD q 0.458 0 0 RG /Type /XObject /Resources<< /Font << /ProcSet[/PDF] /F1 7 0 R /F3 17 0 R q /ProcSet[/PDF/Text] q /Resources<< 1.014 0 0 1.007 391.462 636.879 cm 0 G endobj /Subtype /Form Q /Subtype /Form /Font << /Meta32 Do /Subtype /Form endobj Q endobj 1.014 0 0 1.007 251.439 849.172 cm /ProcSet[/PDF] /BBox [0 0 15.59 16.44] 0 G >> /Meta129 143 0 R 1 i (ix) 3 less than 4 times a number is 17. stream /FormType 1 209 0 obj >> /Type /XObject endobj /Resources<< 171 0 obj /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 271.012 523.204 cm /Meta391 407 0 R >> /Subtype /Form 0 w BT BT /Resources<< q 16.469 5.203 TD /FormType 1 << /ProcSet[/PDF] >> >> endstream 1 i /Meta94 Do 0.369 Tc /Length 54 0 39.216 TD /FormType 1 /Subtype /Form /Meta274 288 0 R endstream /Matrix [1 0 0 1 0 0] /F3 17 0 R /FormType 1 /Meta76 90 0 R /ProcSet[/PDF] Q /Type /XObject /Type /XObject >> q 1 i /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] 1.014 0 0 1.007 251.439 277.035 cm Q << 1.014 0 0 1.007 251.439 383.934 cm 166 0 obj %PDF-1.4 >> 0 g 1 i /F3 17 0 R q << ET /Meta395 Do /ProcSet[/PDF] Q BT /Font << Q << endstream 1.005 0 0 1.007 102.382 799.486 cm q 1.014 0 0 1.007 111.416 583.429 cm Q /Meta159 Do /Meta305 Do (B\)) Tj endstream 1.007 0 0 1.007 271.012 383.934 cm q ET 0.564 G /Matrix [1 0 0 1 0 0] /Resources<< q /Meta357 Do Q endobj 0 G q q 99 0 obj Q /Font << 1 g >> 1.007 0 0 1.007 654.946 347.046 cm >> /Resources<< /FormType 1 /Meta423 Do /Subtype /Form /Resources<< 0.458 0 0 RG q /Leading 253 2x + 3 y equal to 13 and xy = 4 find the value of x cube + 27 y cube, x/3 2/x = 1/2please solve this question. Q q /F3 12.131 Tf /FormType 1 q /F3 17 0 R /Resources<< Q /Matrix [1 0 0 1 0 0] >> /BBox [0 0 15.59 16.44] 0 g BT /FormType 1 /Meta125 Do (\(x ) Tj 1 g 361 0 obj /Font << /Matrix [1 0 0 1 0 0] /Font << /ProcSet[/PDF/Text] /Meta299 313 0 R /Type /XObject 0.297 Tc endobj /Type /XObject q Q /BBox [0 0 549.552 16.44] 1.007 0 0 1.007 130.989 383.934 cm 0.458 0 0 RG /Font << 55 0 obj 1.005 0 0 1.007 102.382 726.464 cm q 1.007 0 0 1.007 45.168 779.913 cm Q 1.014 0 0 1.006 111.416 763.351 cm /FormType 1 endobj >> 114 0 obj Q 0 0 0 722 0 0 0 611 0 722 0 333 0 722 611 0 0 5.203 TD /XHeight 476 >> Q 1 i stream /Meta169 Do >> endobj /ProcSet[/PDF/Text] Q 1 i q q Q /F1 12.131 Tf 1 i /Meta63 Do /F3 17 0 R BT /ProcSet[/PDF] /Resources<< /BBox [0 0 88.214 16.44] /Meta336 350 0 R endstream >> >> 1.007 0 0 1.007 271.012 383.934 cm 0 G q /XObject << >> >> q stream 0.737 w endstream >> Q >> /F3 17 0 R /FormType 1 BT >> /Resources<< q q /Type /XObject 6.746 5.203 TD >> /Meta375 389 0 R /F3 12.131 Tf Q Q q Q 1.007 0 0 1.007 45.168 730.228 cm >> 182 0 obj /BBox [0 0 15.59 16.44] /Length 69 20.21 5.203 TD /Type /XObject /Matrix [1 0 0 1 0 0]

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